The altitude through P is perpendicular to QR.
So if slope of QR =m then slope of altitude will be -1/m
so equation of altitude will be
y-7=(-1/m)(x-3)
hope you can calculate m.if not then you may ask.
I found the slope of the line passing through p to be 4/11
y2-y1/x2-x1
-9-2/-4--8
m=-11/4
Then negative reciprocal so its 4/11
Then i plug it into y=mx+b
and get
4=4/11(3)+b
I can't see to figure it out from here
I found the slope of the line passing through p to be 4/11
y2-y1/x2-x1
-9-2/-4--8
m=-11/4
Then negative reciprocal so its 4/11
Then i plug it into y=mx+b
and get
4=4/11(3)+b
I can't see to figure it out from here
it should not be 4=4/11(3)+b
it should be
7=(4/11)(3)+b
11b=65
b==65/11
so equation will be
y=(4/11)x+65/11
hope this helps.