Can someone show me how to simplify this equation, so it represents a conic section. x^2-2x+y^2-8x+1=0
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Originally Posted by cityismine Can someone show me how to simplify this equation, so it represents a conic section. x^2-2x+y^2-8x+1=0 should the -8x be - 8y? do you know how to complete the square? write as x^2 - 2x + y^2 - 8y = -1 now, complete the squares for the x's and the y's separately. then you should be able to see how to rearrange it. can you continue?
Group and compete the square: I assume you have a typo and mean: Factor: There....what do you have?.
That's exactly how it is in the book, I guess it's typo in the book.
Originally Posted by cityismine That's exactly how it is in the book, I guess it's typo in the book. yes, well, it seems likely to be a typo. you can check the answer in the back of the book, if possible, to see. anyway, galactus gave you the answer: what kind of conic section does this describe? maybe writing it as would help...
The answer in the book is (1,4). So I guess that's the center of the circle.
Originally Posted by cityismine The answer in the book is (1,4). So I guess that's the center of the circle. you should not be guessing. you should be able to tell from the answer galactus gave the equation of a circle can be written in the form: when in this form, the center is and the radius is
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