i have to show how: 1+((4x)/(2x-5))-((15)/((2x^2)-7x+5))
is equal to: (3x+2)/(x-1)
someone please help!!
Sorry, Ms dhju. Hard to tell gender with these screen names.
For assistance using LaTex, go here http://www.mathhelpforum.com/math-help/latex-help/ and ask any question you want after reading the first thread (Latex Tutorial). You can also click on some else's code in any post and see how it was done.
You're right. I retract that. It's just that you had done so much work on it already.....so for being too abrupt, I will finish it:
$\displaystyle 1 + \frac{4x}{2x-5}-\frac{15}{2x^2 - 7x + 5}$
$\displaystyle \frac{(2x-5)(x-1) + 4x(x-1)-15}{(2x-5)(x-1)}$
$\displaystyle \frac{2x^2-7x+5+4x^2-4x-15}{(2x-5)(x-1)}$
$\displaystyle \frac{6x^2-11x-10}{(2x-5)(x-1)}$
$\displaystyle \frac{(3x+2)(2x-5)}{(x-1)(2x-5)}$
$\displaystyle \boxed{\frac{3x+2}{x-1}}$