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Math Help - addition/subtraction of algebraic fractions

  1. #1
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    addition/subtraction of algebraic fractions

    i have to show how: 1+((4x)/(2x-5))-((15)/((2x^2)-7x+5))
    is equal to: (3x+2)/(x-1)
    someone please help!!
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  2. #2
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    im stupid

    dont worry iv solved it
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  3. #3
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    Quote Originally Posted by Jonboy View Post
    I think you mean:

    {\color{blue}{1}} + \frac{4x}{2x-5}-\frac{15}{2x^2} - 7x + {\color{blue}{5}}

    Jonboy, you misread the original post. Should've been:

    1 + \frac{4x}{2x-5}-\frac{15}{2x^2 - 7x + 5}

    Then it's easy after that. OP said he already figured it out, so why bother.
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  4. #4
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    im a she, but yeh apart from that ur right. thanks for helpin anyway. Also, how do you write fractions without having to use all those brackets??
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  5. #5
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    Quote Originally Posted by dhju View Post
    im a she, but yeh apart from that ur right. thanks for helpin anyway. Also, how do you write fractions without having to use all those brackets??

    Sorry, Ms dhju. Hard to tell gender with these screen names.

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  6. #6
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    ...why bother?
    for someone in the future who saw this post and wondered how it's done.
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  7. #7
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    Quote Originally Posted by Jonboy View Post
    for someone in the future who saw this post and wondered how it's done.
    You're right. I retract that. It's just that you had done so much work on it already.....so for being too abrupt, I will finish it:

    1 + \frac{4x}{2x-5}-\frac{15}{2x^2 - 7x + 5}

    \frac{(2x-5)(x-1) + 4x(x-1)-15}{(2x-5)(x-1)}

    \frac{2x^2-7x+5+4x^2-4x-15}{(2x-5)(x-1)}

    \frac{6x^2-11x-10}{(2x-5)(x-1)}

    \frac{(3x+2)(2x-5)}{(x-1)(2x-5)}

    \boxed{\frac{3x+2}{x-1}}
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