i have to show how: 1+((4x)/(2x-5))-((15)/((2x^2)-7x+5))

is equal to: (3x+2)/(x-1)

someone please help!!

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- Jun 30th 2008, 10:43 AMdhjuaddition/subtraction of algebraic fractions
i have to show how: 1+((4x)/(2x-5))-((15)/((2x^2)-7x+5))

is equal to: (3x+2)/(x-1)

someone please help!! - Jun 30th 2008, 11:05 AMdhjuim stupid
dont worry iv solved it (Headbang)

- Jun 30th 2008, 12:37 PMmasters
- Jun 30th 2008, 12:43 PMdhju
im a she, but yeh apart from that ur right. thanks for helpin anyway. Also, how do you write fractions without having to use all those brackets??

- Jun 30th 2008, 01:24 PMmasters

Sorry, Ms dhju. Hard to tell gender with these screen names.

For assistance using LaTex, go here http://www.mathhelpforum.com/math-help/latex-help/ and ask any question you want after reading the first thread (Latex Tutorial). You can also click on some else's code in any post and see how it was done. - Jun 30th 2008, 03:25 PMJonboyQuote:

...why bother?

- Jul 1st 2008, 07:03 AMmasters
You're right. I retract that. It's just that you had done so much work on it already.....so for being too abrupt, I will finish it:

$\displaystyle 1 + \frac{4x}{2x-5}-\frac{15}{2x^2 - 7x + 5}$

$\displaystyle \frac{(2x-5)(x-1) + 4x(x-1)-15}{(2x-5)(x-1)}$

$\displaystyle \frac{2x^2-7x+5+4x^2-4x-15}{(2x-5)(x-1)}$

$\displaystyle \frac{6x^2-11x-10}{(2x-5)(x-1)}$

$\displaystyle \frac{(3x+2)(2x-5)}{(x-1)(2x-5)}$

$\displaystyle \boxed{\frac{3x+2}{x-1}}$