there are two questions.
A diameter of a circle has end points at A(-5,0) and B(9,0).
The equation of the circle is (x^2) + (y^2) - 2x + 2y -3 = 0 .
If C(2,k) lies on the circle, find the value of k and hence prove that triangle ABC is an isosceles right-angled triangle.
my problems are the one highlighted in red and
my answer for k is 7 or -7. so, how can I reject k= -7 ??
i get the equation of the circle by myself, so it might be wrong, if i'm careless, that is.
Given two points P(1,4) , Q(-1,-2). PQ is the diameter.
Show that R(-3,2) lies on the circle and hence prove that angle PRQ is 90 degrees.