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  1. #1
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    circle equation

    I'm just drawing a blank under pressue.

    I only have an hour.

    Find the standard form of the equation for the circle described below:

    Radius: 2sqrt(2) and center (5,-8)

    Thanks
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  2. #2
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    Quote Originally Posted by mankvill View Post
    I'm just drawing a blank under pressue.

    I only have an hour.

    Find the standard form of the equation for the circle described below:

    Radius: 2sqrt(2) and center (5,-8)

    Thanks
    The equation of a circle with center M(h, k) and radius r is:

    (x-h)^2+(y-k)^2=r^2

    Plug in the values you know and then you can transform this equation as you like it.
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  3. #3
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    Here's another that I know how to do, I'm just blanking.

    Parallel line to:

    y = x - 5/3
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  4. #4
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    Quote Originally Posted by earboth View Post
    The equation of a circle with center M(h, k) and radius r is:

    (x-h)^2+(y-k)^2=r^2

    Plug in the values you know and then you can transform this equation as you like it.
    I got (x-5)^2+(y+8)^2=8

    Is that right?
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  5. #5
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    UGH, here's another one. I'm terrible with interval notation:

    Domain And Range in interval notation:

    -2y-5x=-3
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  6. #6
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    Quote Originally Posted by mankvill View Post
    Here's another that I know how to do, I'm just blanking.

    Parallel line to:

    y = x - 5/3
    First I would like to know if I could help you with my previous post.
    Second: Do us and do yourself a favour and start a new thread if you have a new problem to solve.

    Third: A parallel line to

    y = 1 \cdot x- \frac53 must have the same slope, here in this case the slope is m = 1.

    Therefore a parallel line has the equation:

    y = x + c
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  7. #7
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    Quote Originally Posted by mankvill View Post
    I got (x-5)^2+(y+8)^2=8

    Is that right?
    Precisely!
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  8. #8
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    Quote Originally Posted by mankvill View Post
    UGH, here's another one. I'm terrible with interval notation:

    Domain And Range in interval notation:

    -2y-5x=-3
    Are you sure that this is the exact text of your problem? The given equation describes a straight line with D=\mathbb{R} and R=\mathbb{R}
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  9. #9
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    Thank you very much, and I will start new threads from now on.

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  10. #10
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    Quote Originally Posted by mankvill View Post
    UGH, here's another one. I'm terrible with interval notation:

    Domain And Range in interval notation:

    -2y-5x=-3

    D = (-\infty, +\infty)

    R = (-\infty, +\infty)
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