y = cos(2t), y = sin(2t); t is greater than or equal to -pie and less than or equal to pie.
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Originally Posted by cityismine y = cos(2t), y = sin(2t); t is greater than or equal to -pie and less than or equal to pie. . . Therefore . Domain is [-1, 1] and range is [-1, 1] so it's the entire circle.
Just so you know, given and You will always get a circle of radius a and if you have and You will get an ellipse
Last edited by Mathstud28; June 25th 2008 at 10:31 AM. Reason: I said "r" instead of a, for the radius
-pie and less than or equal to pie. Come on...this is math, not a bakery.
The answer in the back of the book is: y=(1/2)x^2-1 Is the answer in the book wrong?
Originally Posted by cityismine The answer in the back of the book is: y=(1/2)x^2-1 Is the answer in the book wrong? Yes For we have that our equation is
Originally Posted by cityismine The answer in the back of the book is: y=(1/2)x^2-1 Is the answer in the book wrong? If the parametric equations were actually and then the cartesian equation would be ........ If the parametric equations were actually and then the cartesian equation would be ........ Are the equations you posted correct?
Yes, I posted them correctly, I just double checked. I guess it's a typo in the book.
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