Hey I am really stuck on this problem:

2x^2 - 3xy - 2y^2 + 10 = 0

I know that when AC<0 then the rotation is for a Hyperbola, 2(-2)=-4

Now the formula for finding the degree of axis rotation is cot 2q=(A-C)/B

so (2-(-2))/-3 = -4/3, and this is where I am stuck, I can do the rest after I have q but whatever i try does not seem to be working

I need to solve cot q = -4/3