Hey I am really stuck on this problem:
2x^2 - 3xy - 2y^2 + 10 = 0
I know that when AC<0 then the rotation is for a Hyperbola, 2(-2)=-4
Now the formula for finding the degree of axis rotation is cot 2q=(A-C)/B
so (2-(-2))/-3 = -4/3, and this is where I am stuck, I can do the rest after I have q but whatever i try does not seem to be working
I need to solve cot q = -4/3
Thank you, i have another problem now with that answer however, I have to plug in xcosA - ysinB and xsinB + ycosA
In my book the give the example xcos(pie/4) - ysin(pie/4) = x(1/sqrt2)-y(1/sqrt2).
How do i plug in 71.565?