URgent HELP!!

Hello, Brooke!

Since you didn't explain where your difficulty lies,
. . I'll just give you the answers.

Quote:

1. Find the inverse of $f(x)\:=\:\frac{x-5}{3x+4}$

$f^{\text{-}1}(x)\;=\;\frac{4x+5}{1-3x}$

Quote:

2. Find the partial fraction decomposition: $\frac{x^2-x-21}{(x^2+4)(2x-1)} \;= \;\frac{Ax+B}{x^2+4} + \frac{C}{2x-1}$

$\frac{3x + 1}{x^2+4} - \frac{5}{2x-1}$

Quote:

3. Use synthetic division: $(4x^3-3x^2-5x+6) \div(x-3)$

Code:

3 | 4 -3 5 6 | 12 27 96 --------------- 4 9 32 102

Quotient: $4x^2 + 9x + 32$ . . . Remainder: $102$