Solve the inequality:
$\displaystyle y^3 - 6y^2 + 8y < 0$
So here is what I did, just following the steps to follow a normal equation
y (y² - 6y + 8) < 0
y (y - 2) (y - 4) < 0
So what are the answers and how do i express them?
Solve the inequality:
$\displaystyle y^3 - 6y^2 + 8y < 0$
So here is what I did, just following the steps to follow a normal equation
y (y² - 6y + 8) < 0
y (y - 2) (y - 4) < 0
So what are the answers and how do i express them?
Hi
A product is negative iff it has an odd number of negative term(s). In this case, there are three terms. ($\displaystyle y$, $\displaystyle y-2$ and $\displaystyle y-4$) As the only odd numbers in $\displaystyle \{1,2,3\}$ are 1 and 3, the product is negative if one term is negative or if the three are negative. Does it help ?