So here is what I did, just following the steps to follow a normal equation
y (y² - 6y + 8) < 0
y (y - 2) (y - 4) < 0
So what are the answers and how do i express them?
A product is negative iff it has an odd number of negative term(s). In this case, there are three terms. ( , and ) As the only odd numbers in are 1 and 3, the product is negative if one term is negative or if the three are negative. Does it help ?
A product is negative iff it has an odd number of negative term(s). In this case, there are three terms. ( , and ) As the only odd numbers in are 1 and 3, the product is negative if one term is negative or if the three are negative. Does it help ?
So whats the solution? I mean a solution expressed without a graph.