The question is to find the direction cosines & angles of each line, but one of them is in scalar form, like this: 3x + 5y + 2 = 0 How can I find the direction of the vector of the line from scalar form? Or, how can I get this into vector form?
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Originally Posted by theowne The question is to find the direction cosines & angles of each line, but one of them is in scalar form, like this: 3x + 5y + 2 = 0 How can I find the direction of the vector of the line from scalar form? Or, how can I get this into vector form? Draw the line. A vector in the direction of the line should now be obvious ......
Originally Posted by theowne The question is to find the direction cosines & angles of each line, but one of them is in scalar form, like this: 3x + 5y + 2 = 0 How can I find the direction of the vector of the line from scalar form? Or, how can I get this into vector form? Rewrite the equation: is the normal vector of the line. You get the direction vector of the line if you change the order of the components and change the sign at one component: The direction vector is now: or Remark: This procedure works only in 2D.
Originally Posted by theowne ... 3x + 5y + 2 = 0 ... how can I get this into vector form? Change this equation into parametric form: Now you can rewrite this form into an equation in vector form:
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