# Algebra!!! Oh Noez!!!

• Jun 12th 2008, 05:24 AM
Graffitixgirl
Algebra!!! Oh Noez!!!
ok is been a while, and im now completley stuck with one last question. i tried all the methods i have up my sleeve and they STILL DONT WORK

its about finding regions and stuff...
so yeah

a:y>=-4 x=<3 y<x
b:x<0 y=<2 y>=x-3
c:x>1 y=<2 y>=x
d:y=<5 y>=x y>=-x
e:y<4 y>=x+1 y>=1-x
f:y>=x y=<2x y<3

HALP!!! (Crying)(Crying)(Crying)

but i will be working on this as well, so just plz tell me if u only noe even 1 of the answers k? (Itwasntme)
• Jun 12th 2008, 05:28 AM
sean.1986
• Jun 12th 2008, 05:31 AM
Graffitixgirl
Oops!
oh we need to find the region... or smth liek that(Nerd)
• Jun 12th 2008, 05:37 AM
sean.1986
Any way you might be able to post it exactly as it's written?
• Jun 12th 2008, 05:42 AM
Graffitixgirl
soz
thats the closest i could get it to. the >= is the symbols that means more than or equal to, and its vice versa for =<
• Jun 12th 2008, 05:45 AM
sean.1986
Maybe you can post a similar question and its answer?
• Jun 12th 2008, 05:47 AM
Graffitixgirl
thats the problem. i dunno how to do this question... D:
• Jun 12th 2008, 06:04 AM
masters
Maybe these are like "feasible regions" in a linear programming model!?
• Jun 12th 2008, 06:13 AM
Graffitixgirl
basically the question just askds to find the region that is described by the inequalities (my first post)
• Jun 12th 2008, 06:22 AM
sean.1986
Well the domain of the first one is...

-4 < x <= 3

And the range is...

-4 <= y < 3

You mean that?
• Jun 12th 2008, 06:24 AM
masters
Maybe something like this for (a) with vertices at (-4,-4), (3, -4), (3, 3):