Results 1 to 2 of 2

Math Help - Graphs

  1. #1
    Member
    Joined
    Jan 2008
    Posts
    132

    Graphs

    The equation of a curve is given as y = [(ax^2 + bx + c)/(x+d)], where a, b, c and d are constants. the equations of the asymptotes are x=2 and y= 3-2x.

    i) Write down the value of d [I know that d = -2]
    ii) Fidn the value of a and show that b = 7. [Do I have to express the given equation as partial fractions?]

    iii) Given that the curve has a stationary point where x = 1, find the value of c and the x-coordinate of the other stationary point.

    Thank you for your help!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Mathstud28's Avatar
    Joined
    Mar 2008
    From
    Pennsylvania
    Posts
    3,641
    Quote Originally Posted by Tangera View Post
    The equation of a curve is given as y = [(ax^2 + bx + c)/(x+d)], where a, b, c and d are constants. the equations of the asymptotes are x=2 and y= 3-2x.

    i) Write down the value of d [I know that d = -2]
    ii) Fidn the value of a and show that b = 7. [Do I have to express the given equation as partial fractions?]

    iii) Given that the curve has a stationary point where x = 1, find the value of c and the x-coordinate of the other stationary point.

    Thank you for your help!
    For ii) I would synthetically divide

    For iii) take the derivative, set it equal to zero and use the other information to finally solve for c
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Graphs
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: March 3rd 2010, 06:54 AM
  2. Graphs
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 2nd 2010, 08:25 PM
  3. Replies: 0
    Last Post: December 29th 2009, 08:08 PM
  4. graphs
    Posted in the Discrete Math Forum
    Replies: 0
    Last Post: April 30th 2008, 09:08 PM
  5. Help with graphs
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: October 20th 2007, 10:03 PM

Search Tags


/mathhelpforum @mathhelpforum