Write the domain in interval notation notation and determine the y-intercept.
g(x)= x - 3
f(x)= 1/ x-3
Thanks.
For g(x) there are no restrictions on the domain so the domain would be $\displaystyle ( -\infty, \infty )$. You do the range.
For f(x) I presume you mean
$\displaystyle f(x) = \frac{1}{x - 3}$
PLEASE use parenthesis!!
Here the domain is all reals except for x = 3, so that would be $\displaystyle (-\infty, -3) \cup (-3, \infty )$. Again I will leave the range to you. (Hint: What value can f(x) not take?)
-Dan