1. ## Functions

Given :

f(x) = 5x + 3, x > 0
g(x) = 3/x , x > 0
gg(x) = x, x > 0
h(x) = 25x + 18, x > 0

express h in terms of one or both f and g.

The answer that I was given is h(x) = 6f(x) - 5 gg(x). Is it possible to also express h as h(x) = f(5x) + 15??

2. $h(x) = 25x + 18$
${\color{blue}f(5x)} + 15 = {\color{blue}5(5x) + 3} + 15 = 25x + 18 = h(x)$