Can you tell us how you arrived at your answer?Originally Posted by kwtolley
RonL
The amount of a radioactive tracer remaining after t days is given by A=Ao e^-0.058t, where Ao is the starting amount at the beginning of the time period. How many days will it take for one half of the original amount to decay? My answer is 12 days is that right. Thanks for looking at my answer.
Hello, kwtolley!
You probably did it correctly . . . it's hard to see your work from here.
The amount of a radioactive tracer remaining after t days is given by:
where is the starting amount at the beginning of the time period.
How many days will it take for one half of the original amount to decay?
The question is: When is: ?
The equation is: .
Take logs: .
Therefore: .