Given z = -1 - sqrt(3)i What is the value of theta? I got pi/3 but that is not right, the correct answer is -2pi/3 Thanks
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Originally Posted by taurus Given z = -1 - sqrt(3)i What is the value of theta? I got pi/3 but that is not right, the correct answer is -2pi/3 Thanks is your reference angle Think of -1 as being the x coordinate and as your y This you put the point in quadrant III rotated down from the negative x-axis. I hope this helps.
i still dont get it?
Hello, taurus! Did you make a sketch? Given: . What is the value of ? Code: | | | -1 | - - + - - * - - - - : /| _ : / | -√3 : / | : / | :/ | * | Can you see that the angle is: . ? In radians: .
| | | -1 | - - + - - * - - - - : /| _ : / | -√3 : / | : / | :/ | * |
How did u get the -2pi/3? i did this: -120*pi/360 =pi/3 which is not right?
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