I'm not sure if I've put this in the correct section, but here goes...
Please may someone help me with this question. I understand how to do (a) but not (b).
The gradient of a curve at the point (x,y) is given by the differential equation
dy/dx = (2-x)/y
a) Find the general solution of dy/dx = (2-x)/y
b) Given that the curve passes through the point (4,2) show that the curve is a circle and find its radius and the coordinates of its centre.
Thank you all
You should have
Originally Posted by racheltllong
where A = K - 4 is just as arbitrary as K and K = 2C is just as arbitrary as C and C is an arbitrary constant.
You can solve for A using the given condition, right?
And you can recognise the equation of a circle. And get the radius and coordinates of centre from that equation, right?
Is this really something taught in Pre-Calc ?
He probably did not see the calculus' forum, but it's not taught at pre-calc. level.
I was about to say, I'm missing out.