Results 1 to 3 of 3

Math Help - quick query!

  1. #1
    Newbie
    Joined
    Jun 2008
    Posts
    2

    quick query!

    Hi, just did a search for maths forum and here we are!!

    if:

    A/B^0.666 = C

    how do i find B if i only have A & C!

    thanks a lot
    Steve
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    May 2008
    Posts
    186
    A/C = B^0.666

    I'm guessing the 0.666 can be interpreted as 2/3?

    A/C = B^(2/3) = (B^2)^(1/3)

    Cube A/C then take the square root of the result.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jun 2008
    Posts
    2
    Quote Originally Posted by sean.1986 View Post
    A/C = B^0.666

    I'm guessing the 0.666 can be interpreted as 2/3?

    A/C = B^(2/3) = (B^2)^(1/3)

    Cube A/C then take the square root of the result.
    absolute legend, thanks
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. A Simple Query.
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: November 3rd 2010, 07:10 AM
  2. exp&log functions query
    Posted in the Algebra Forum
    Replies: 1
    Last Post: March 30th 2009, 01:33 PM
  3. probability query?
    Posted in the Statistics Forum
    Replies: 4
    Last Post: November 12th 2008, 10:17 PM
  4. query
    Posted in the Algebra Forum
    Replies: 1
    Last Post: January 4th 2008, 02:41 AM
  5. Quick complex analysis query
    Posted in the Calculus Forum
    Replies: 2
    Last Post: November 18th 2007, 12:14 PM

Search Tags


/mathhelpforum @mathhelpforum