The line y=2x- 3 intersects the curve y=x^2+x-15 at the points

(a)(3,3)and(4,5)

(b)(-3,-9)and(4,5)

(c)(3,3)and(-4,-11)

(d)(-3,-9)and(-4,-11).

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- Jul 4th 2006, 10:44 AMbobby77Intersection of curves
The line y=2x- 3 intersects the curve y=x^2+x-15 at the points

(a)(3,3)and(4,5)

(b)(-3,-9)and(4,5)

(c)(3,3)and(-4,-11)

(d)(-3,-9)and(-4,-11). - Jul 4th 2006, 11:21 AMCaptainBlackQuote:

Originally Posted by**bobby77**

$\displaystyle

2x-3=x^2+x-15

$,

so:

$\displaystyle

x^2-x-12=0

$

Now trying the candidates for $\displaystyle x$, we find that ,$\displaystyle x=-3$ satisfies

this equation as does $\displaystyle x=4$, so (b) must be the answer (assuming the

$\displaystyle y$'s are OK which I suppose we can).

RonL