9. A boy throws a ball with speed V m/s at an angle of 45 degrees to the horizontal.
a) Derive expressions for the horizontal and vertical components of the displacement of the ball from the point of projection
b) Hence show that the Cartesian equation of the path o the ball is y = x- gx^2/ (V^2)
c) the boy is now standing on a hill inclined at an angle A to the horizontal. He throws the ball at the same angle of elevation of 45 degress and at the same speed of V m/s. If he can throw the ball 60 metres down the hill but only 30 metres up the hill, use the result in part (b) to show that
tan A = 1 - 30gcosA/V^2 = 60gcosA/V^2 -1
and hence that tan A = 1/3
I know how to do a,b but don't know how to do C, please help me