[(x-h)^2 / a^2] - [(y-k)^2 / b^2] = 1 (or < 1 in this case).
h and k are both zero in this case.
Foci: (h +|- c, k)
Vertices: (h +|- a, k)
Asymptotes: (y - k) = (+|-b/a)(x-h)
I have never drawn as an inequality, but it seems clear enough.
If you hang around, someone might just send a picture generated by software. Otherwise, it seems reasonable to shade parts of the graph that would satisfiy the constraints, and make the boundaries dotted lines.