Trig functions

cassie · June 2nd 2005, 07:30 AM

If sin^2 of theta = 1/2 and pi< theta < 3pi/2 (quadrant III) then theta= ?

I have no idea how to do these type of problems! Please Help!

**askmemath** · June 2nd 2005, 08:09 AM

$ \sin^2 \theta = \frac {1} {2} \Rightarrow \sin \theta= \frac {1}{\sqrt{2}} \Rightarrow \theta= -\frac {\pi} {4} \Rightarrow \theta= \pi + \frac{\pi}{4} \Rightarrow \theta= 5\frac{\pi}{4} $

**vms** · July 11th 2005, 10:38 PM

Originally Posted by askmemath

$ \sin^2 \theta = \frac {1} {2} \Rightarrow \sin \theta= \frac {1}{\sqrt{2}} \Rightarrow \theta= -\frac {\pi} {4} \Rightarrow \theta= \pi + \frac{\pi}{4} \Rightarrow \theta= 5\frac{\pi}{4} $

sine of theta must be taken as negative sqaure root of half here.
then the value of theta will be 5Pi/4

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