1. ## Trig functions

If sin^2 of theta = 1/2 and pi< theta < 3pi/2 (quadrant III) then theta= ?

2. $
\sin^2 \theta = \frac {1} {2}
\Rightarrow \sin \theta= \frac {1}{\sqrt{2}}

\Rightarrow \theta= -\frac {\pi} {4}

\Rightarrow \theta= \pi + \frac{\pi}{4}

\Rightarrow \theta= 5\frac{\pi}{4}
$

$
\sin^2 \theta = \frac {1} {2}
\Rightarrow \sin \theta= \frac {1}{\sqrt{2}}

\Rightarrow \theta= -\frac {\pi} {4}

\Rightarrow \theta= \pi + \frac{\pi}{4}

\Rightarrow \theta= 5\frac{\pi}{4}
$
sine of theta must be taken as negative sqaure root of half here.
then the value of theta will be 5Pi/4