Hi

This is a fraction hence it exists iff the denominator does not equal 0 :

To find the range, start from then multiply by 2 : then add 1...

is one-to-one iff for any belonging to the domain of . To find , you can write and solve this for : it'll give .(b) Is g(v) one-to-one? Find g−1 (v), the inverse function of g(v), and state the domain and range.