so i'm trying to help my little brother with his math homework, but i can't recall some of the things i ned to know. basically, the problem states that some rational function, r(x) has a vert. asymptote at x = 3, a vert. asymptote at y = 2, and a hole at (2, -2).
is there some sort of formula i'm supposed to know how to use? because the instructions request that i "put in the factor[s] that would account" for the asymptotes and "find a."
Why does adding 2 to the function create an asymptote at y=2? I was under the idea that in order to create a horizontal asymptote, you must have the same degree in the numerator and denominator, and, in this case, the leading coefficient of the numerator must be twice the leading coefficient of the denominator?
your function seems correct, I'm just confused. Thanks a lot if you can explain!
I suppose I can see that 2/1 would meet those qualifications, I was just unsure of how it applies itself to the rest of the function...I'm no algebra wiz, so
Edit: 1. So the required function I found can also be written as .
2. The thread http://www.mathhelpforum.com/math-he...tml#post145259 is of related interest.