1. (sin2x + cos2x) ^2=1
solutions are in the interval [0, 2pi)
using double angle formulas find sin2u , cos2u, and tan2u in:
2. cot u = -6, 3pi/2< u < 2pi
rewrite the expression in terms of the first power of cos:
i get stuck in between theses problems, its usually the factoring...