You see that . Then you just have to apply the well known formula .using double angle formulas find sin2u , cos2u, and tan2u in:
2. cot u = -6, 3pi/2< u < 2pi
For , we have that it's equal to .
1. (sin2x + cos2x) ^2=1
solutions are in the interval [0, 2pi)
using double angle formulas find sin2u , cos2u, and tan2u in:
2. cot u = -6, 3pi/2< u < 2pi
rewrite the expression in terms of the first power of cos:
3. sin^4x*cos^2x
i get stuck in between theses problems, its usually the factoring...