I have a calc final tomorrow and I can't seem to figure this problem out. Please help. He gave us the answer which was 1.500, but I don't know how he got it.
Let logb A = 5 and logb B =-2. Find logb 2√AB.
I have a calc final tomorrow and I can't seem to figure this problem out. Please help. He gave us the answer which was 1.500, but I don't know how he got it.
Let logb A = 5 and logb B =-2. Find logb 2√AB.
I'm stuck on logb (2). When I add it to the rest of the problem it came out to be a completely different answer.
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I dont think that two should be there
Because if it wasnt you would just ahve $\displaystyle \frac{1}{2}\bigg[\log_b(A)+\log_b(B)\bigg]=\frac{1}{2}\bigg[5+-2\bigg]=\frac{1}{2}\cdot{3}=\frac{3}{2}=1.5$