Find the equation of the line containing the point (-1,4) and perpendicular to the line y= -3/2x - 4 y= 2/3x - 4 Is that it? Or is it y= 2/3x + 4 or something else?
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y=(-3/2)x-4 ----> gradient=(-3/2) perpendicular -----> gradient = 2/3 y=(2/3)x+c 4=(-2/3)+c c=14/3 y=(2/3)x+(14/3)
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