Find the equation of the line containing the point (-1,4) and perpendicular to the line y= -3/2x - 4
y= 2/3x - 4
Is that it? Or is it y= 2/3x + 4 or something else?
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Find the equation of the line containing the point (-1,4) and perpendicular to the line y= -3/2x - 4
y= 2/3x - 4
Is that it? Or is it y= 2/3x + 4 or something else?
y=(-3/2)x-4 ----> gradient=(-3/2)
perpendicular -----> gradient = 2/3
y=(2/3)x+c
4=(-2/3)+c
c=14/3
y=(2/3)x+(14/3)