Find the equation of the line containing the point (-1,4) and perpendicular to the line y= -3/2x - 4

y= 2/3x - 4

Is that it? Or is it y= 2/3x + 4 or something else?

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- May 11th 2008, 07:21 PMMadPerpendicular Lines
Find the equation of the line containing the point (-1,4) and perpendicular to the line y= -3/2x - 4

y= 2/3x - 4

Is that it? Or is it y= 2/3x + 4 or something else? - May 11th 2008, 08:53 PMSingular
y=(-3/2)x-4 ----> gradient=(-3/2)

perpendicular -----> gradient = 2/3

y=(2/3)x+c

4=(-2/3)+c

c=14/3

y=(2/3)x+(14/3)