The equation is: $\displaystyle 3 tan 2x - 4 = 6 $

and I can get this equation down to $\displaystyle \frac{6tanx}{(3-3tan^2x)} = \frac{10-tan^2x}{3-3tan^2x}$ but no further.

the other problem is i can't prove the identity: $\displaystyle \frac{sin2x + sin6x}{sin10x - sin2x} = \frac{cos2x}{cos6x}$ but i don't even know where to start

I am starting to panic as this is a take home test due tomorrow and I am really getting stuck. Thanks a lot!