Help....
1. Graph y=-x^2+2x+1
Coordinates of all the intercepts:
Coordinates of the vertex
Can someone work through these and help...-thanks!
To find the intercepts of any function set the opposite variable equal to zero and solve the resulting equation
i.e x-intercept set y=0 solve for x to complete the ordered pair.
y-intercept set x=0 and solve for y.
There are a few different ways to find the intercept, what method are you using?
Good luck.
this is a downward opening parabola.
to find the x-intercepts, set y = 0 and solve for x. to find the y-intercept, set x = 0 and solve for y
you can find the vertex either by completing the square (if a parabola is written in the form $\displaystyle y = a(x - h)^2 + k$, then the vertex is$\displaystyle (h,k)$), or using the formula that for the vertex, $\displaystyle x = \frac {-b}{2a}$. thus the vertex occurs at $\displaystyle \left(\frac {-b}{2a}, f \left( \frac {-b}{2a}\right) \right)$ where $\displaystyle f(x)$ is the parabola