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Math Help - Graph!

  1. #1
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    Graph!

    Help....

    1. Graph y=-x^2+2x+1
    Coordinates of all the intercepts:

    Coordinates of the vertex


    Can someone work through these and help...-thanks!
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by mathhelplz View Post
    Help....

    1. Graph y=-x^2+2x+1
    Coordinates of all the intercepts:

    Coordinates of the vertex


    Can someone work through these and help...-thanks!
    To find the intercepts of any function set the opposite variable equal to zero and solve the resulting equation

    i.e x-intercept set y=0 solve for x to complete the ordered pair.

    y-intercept set x=0 and solve for y.

    There are a few different ways to find the intercept, what method are you using?

    Good luck.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mathhelplz View Post
    Help....

    1. Graph y=-x^2+2x+1
    Coordinates of all the intercepts:

    Coordinates of the vertex


    Can someone work through these and help...-thanks!
    this is a downward opening parabola.

    to find the x-intercepts, set y = 0 and solve for x. to find the y-intercept, set x = 0 and solve for y

    you can find the vertex either by completing the square (if a parabola is written in the form y = a(x - h)^2 + k, then the vertex is  (h,k)), or using the formula that for the vertex, x = \frac {-b}{2a}. thus the vertex occurs at \left(\frac {-b}{2a}, f \left( \frac {-b}{2a}\right) \right) where f(x) is the parabola
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