I know that the vertical asymptote is 2 and the domain is 2 to infinite. What is the range? $\displaystyle f(x)=log_2(x-2)+1$
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Originally Posted by theevilp0ptart I know that the vertical asymptote is 2 and the domain is 2 to infinite. What is the range? $\displaystyle f(x)=log_2(x-2)+1$ The range of $\displaystyle \log_2(x)$ is all real numbers Veterical and horizontal shifts will not change the range from all real numbers.
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