Find the equation of the circle with center at (-2, 3) and which passes through (-1, 4).
My answer:
$\displaystyle (x+1)^2 + (y-3)^2=1$
Hows it look?
Hello,
Hmm...not so good :/
The general equation of a circle is $\displaystyle (x-x_O)^2+(y-y_O)^2=R^2$
Where the center is O ($\displaystyle x_O;y_O$). Here, the center is (-2,3).
For the radius, replace : you know that (-1,4) is on the circle. So replace x=-1 and y=4 to get Rē.