Results 1 to 5 of 5

Math Help - Domain And Range

  1. #1
    Newbie
    Joined
    Oct 2007
    Posts
    15

    Domain And Range

    hello, i need some help with this problem please!!:

    Given

    y= 1/x-3

    a)find the domain
    b)find the range


    thanks
    Last edited by subzero06; May 3rd 2008 at 08:58 PM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Reckoner's Avatar
    Joined
    May 2008
    From
    Baltimore, MD (USA)
    Posts
    1,024
    Thanks
    75
    Awards
    1

    Smile

    Quote Originally Posted by subzero06 View Post
    y= 1/x-3
    Do you mean y = \frac{1}{x} - 3 (as it's written) or y = \frac{1}{x - 3}?

    In either case, the domain is the set of values of x for which the function is defined. Notice that you have a variable in the denominator of your function. Since division by zero is undefined, what does that tell you about the values that x can take on?

    The range will be all of the possible values of y. For y = \frac{1}{x} - 3, note that \frac{1}{x} can never be zero; what does that tell you about the possible values of y?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Oct 2007
    Posts
    15
    Quote Originally Posted by Reckoner View Post
    Do you mean y = \frac{1}{x} - 3 (as it's written) or y = \frac{1}{x - 3}?

    In either case, the domain is the set of values of x for which the function is defined. Notice that you have a variable in the denominator of your function. Since division by zero is undefined, what does that tell you about the values that x can take on?

    The range will be all of the possible values of y. For y = \frac{1}{x} - 3, note that \frac{1}{x} can never be zero; what does that tell you about the possible values of y?
    yeah the second 1
    y=1/(x-3)

    so X cannot be 3? so is any number not = 3?
    and Y is any number but not zero?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by subzero06 View Post
    yeah the second 1
    y=1/(x-3)

    so X cannot be 3? so is any number not = 3?
    and Y is any number but not zero?
    Yes.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor Reckoner's Avatar
    Joined
    May 2008
    From
    Baltimore, MD (USA)
    Posts
    1,024
    Thanks
    75
    Awards
    1
    Quote Originally Posted by subzero06 View Post
    yeah the second 1
    y=1/(x-3)

    so X cannot be 3? so is any number not = 3?
    and Y is any number but not zero?
    Correct! The domain is all real numbers x\neq3, and the range is all real numbers y\neq0. Good job.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Domain and range
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 14th 2010, 03:09 AM
  2. Domain and Range
    Posted in the Pre-Calculus Forum
    Replies: 9
    Last Post: January 13th 2010, 08:12 AM
  3. Domain And Range
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: December 12th 2009, 01:31 PM
  4. Replies: 6
    Last Post: September 16th 2009, 07:25 AM
  5. Domain and range?
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: April 22nd 2008, 05:45 AM

Search Tags


/mathhelpforum @mathhelpforum