Thread: Domain And Range

hello, i need some help with this problem please!!:

Given

y= 1/x-3

a)find the domain
b)find the range


thanks

Originally Posted by subzero06

y= 1/x-3

Do you mean (as it's written) or ?

In either case, the domain is the set of values of for which the function is defined. Notice that you have a variable in the denominator of your function. Since division by zero is undefined, what does that tell you about the values that can take on?

The range will be all of the possible values of . For , note that can never be zero; what does that tell you about the possible values of ?

Originally Posted by Reckoner

Do you mean (as it's written) or ?

In either case, the domain is the set of values of for which the function is defined. Notice that you have a variable in the denominator of your function. Since division by zero is undefined, what does that tell you about the values that can take on?

The range will be all of the possible values of . For , note that can never be zero; what does that tell you about the possible values of ?

yeah the second 1
y=1/(x-3)

so X cannot be 3? so is any number not = 3?
and Y is any number but not zero?

Originally Posted by subzero06

yeah the second 1
y=1/(x-3)

so X cannot be 3? so is any number not = 3?
and Y is any number but not zero?

Yes.

Originally Posted by subzero06

yeah the second 1
y=1/(x-3)

so X cannot be 3? so is any number not = 3?
and Y is any number but not zero?

Correct! The domain is all real numbers , and the range is all real numbers . Good job.