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Math Help - Function questions

  1. #1
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    Function questions

    I thought I knew how to do these but apparently I dont since I got it wrong on my test.

    f(x)= -x^2+4x-1

    Problem says to write in standard form and state the coordinates of the vertex and graph which I have a general idea of how to do. How would put this in standard form to get the vertex and would the porabola open up or down?
    Last edited by av8or91; April 28th 2008 at 07:12 PM.
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  2. #2
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    Quote Originally Posted by av8or91 View Post
    I thought I knew how to do these but apparently I dont since I got it wrong on my test.

    f(x)= -x^2+4x-1

    Problem says to write in standard form and state the coordinates of the vertex and graph which I have a general idea of how to do. How would put this in standard form to get the vertex and would the porabola open up or down?
    i THINK to do this you would (correct me if im wrong guys)

    x^2 -4x = -1
    (X^2-4x+4)-4=-1
    (x-2)^2 -3= f(x)


    i believe its something like this..
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  3. #3
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    Quote Originally Posted by Legendsn3verdie View Post
    i THINK to do this you would (correct me if im wrong guys)

    x^2 -4x = -1
    (X^2-4x+4)-4=-1
    (x-2)^2 -3= f(x)


    i believe its something like this..
    ...Looks like you took my advice...yes you are correct
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  4. #4
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    I have one more I need some help with.

    f(x)= x^4 -3x^3 - 3x^2 +11x - 6

    I Used synthetic division to find the complete factored form, with x=1 multiplicity 2. After that I got (x-1)^2 (x-3) (x+2)

    Now it says to solve using the factored form?????
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  5. #5
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    Quote Originally Posted by av8or91 View Post
    I have one more I need some help with.

    f(x)= x^4 -3x^3 - 3x^2 +11x - 6

    I Used synthetic division to find the complete factored form, with x=1 multiplicity 2. After that I got (x-1)^2 (x-3) (x+2)

    Now it says to solve using the factored form?????
     f(x)= x^4  -3x^3 - 3x^2 +11x - 6

     f(x)= x^4  -x^3 -2x^3 +2x^2 - 5x^2 + 5x + 6x - 6

     f(x)= x^3(x-1) -2x^2(x-1) - 5x(x-1)+ 6(x - 1)

     f(x)= (x-1)(x^3 -2x^2 - 5x+ 6)

     f(x)= (x-1)(x^3 - x^2 -x^2 + x - 6x+ 6)

     f(x)= (x-1)(x^2(x -1) -x(x-1) - 6(x-1))

     f(x)= (x-1)^2(x^2 -x - 6)

     f(x)= (x-1)^2(x^2 -3x + 2x - 6)

     f(x)= (x-1)^2(x-3)(x + 2)


    Thanks to the answer you posted I did the factoring
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