what is the f ^-1 inverse of f (x) = x+1/x-1 How would I work this problem? Thank you !
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So to find the inverse, switch the x's and y's. $\displaystyle x=\frac{y+1}{y-1}$ $\displaystyle xy-x=y+1$ $\displaystyle y(x-1)=1+x$ $\displaystyle f^{-1}(x)=\frac{x+1}{x-1}$
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