Logarithms in Exponents

**ParadoxKing** · April 28th 2008, 07:07 AM

Okay I'm having a small issue with logarithms. I have this problem assigned by my teacher:

. How precisely do I solve this problem? And moreover what is the general rule to solving other problems like this?

**Isomorphism** · April 28th 2008, 07:12 AM

Originally Posted by ParadoxKing

Okay I'm having a small issue with logarithms. I have this problem assigned by my teacher:

. How precisely do I solve this problem? And moreover what is the general rule to solving other problems like this?

Hint: $\log_2 2^4 = 4\log_2 2$

**Danshader** · April 28th 2008, 07:15 AM

Hello there,

well i hope you know that you can simplify the exponential:
$e^{log_2 16} <br /> = e^{log_2 2^4}<br /> = e^{4log_2 2}<br /> = e^4$

**ParadoxKing** · April 28th 2008, 07:17 AM

Thanks, that helped a lot.

**finch41** · April 28th 2008, 02:18 PM

actually you cannot solve the problem since there is no variable for which to solve

it seems to simplify to e^4 + 2

agreement?

Thread: Logarithms in Exponents