Logarithms in Exponents

• Apr 28th 2008, 08:07 AM
Logarithms in Exponents
Okay I'm having a small issue with logarithms. I have this problem assigned by my teacher: Attachment 6089. How precisely do I solve this problem? And moreover what is the general rule to solving other problems like this?
• Apr 28th 2008, 08:12 AM
Isomorphism
Quote:

Okay I'm having a small issue with logarithms. I have this problem assigned by my teacher: Attachment 6089. How precisely do I solve this problem? And moreover what is the general rule to solving other problems like this?

Hint: $\log_2 2^4 = 4\log_2 2$
• Apr 28th 2008, 08:15 AM
Hello there,

well i hope you know that you can simplify the exponential:
$e^{log_2 16}
= e^{log_2 2^4}
= e^{4log_2 2}
= e^4$
• Apr 28th 2008, 08:17 AM
Thanks, that helped a lot.
• Apr 28th 2008, 03:18 PM
finch41
actually you cannot solve the problem since there is no variable for which to solve

it seems to simplify to e^4 + 2

agreement?