How would I solve the x and y intercepts of this and find its horizontal asymptotes: $\displaystyle h(x)=log_2(x-1)+2$
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Originally Posted by theevilp0ptart How would I solve the x and y intercepts of this? $\displaystyle h(x)=log_2(x-1)+2$ You should essentially be asking: x-intercept ==> For what x, is h(x) = 0 ? y-intercept ==> If x = 0, what is h(x)? Can you try now?
Originally Posted by theevilp0ptart How would I solve the x and y intercepts of this? $\displaystyle h(x)=log_2(x-1)+2$ Double post Originally Posted by theevilp0ptart How would I solve the x and y intercepts of this and find its horizontal asymptotes: $\displaystyle h(x)=log_2(x-1)+2$ x-intercept: Solve $\displaystyle 0 = \log_2(x - 1) + 2$. Is there a real solution? y-intercept: Substitute x = 0. Is there a real solution? Horizontal asymptote: None. Vertical asymptote: Solve x - 1 = 0 ......
Last edited by mr fantastic; Apr 28th 2008 at 03:11 AM. Reason: Moved reply from the double post
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