If f(x)=x(x-1)(x-4)^2, use interval notation to give all values of x where f(x)>0. My answer is (0,1) u (4,infy), thanks for looking it over with me.
$\displaystyle f(x) \to +\infty$ as $\displaystyle x \to \pm \infty$, and its roots are $\displaystyle 0,1,4$, with the last having a multiplicity of 2 (and so the function just touches the x-axis at $\displaystyle x=4$. So $\displaystyle f(x)>0$ in:Originally Posted by kwtolley
$\displaystyle (-\infty,0) \cup (1,4) \cup (4,\infty)$
RonL