If f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0. My answer would be (0,1) u (3,infinity) but not sure. thanks for checking.
The roots of $\displaystyle f(x)$ are: $\displaystyle -3,\ 0,\ 1$. $\displaystyle f(x)$ goes to $\displaystyle +\infty$ as $\displaystyle x \to \infty$ andOriginally Posted by kwtolley
to $\displaystyle -\infty$ as $\displaystyle x \to -\infty$, so the set of values for which $\displaystyle f(x)>0$ is:
$\displaystyle
(-3,0) \cup (1,\infty)
$
RonL