If f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0. My answer would be (0,1) u (3,infinity) but not sure. thanks for checking.

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- Jun 25th 2006, 01:18 AMkwtolleyalgebra and trigonometry with analytic geometry problem
If f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0. My answer would be (0,1) u (3,infinity) but not sure. thanks for checking.

- Jun 25th 2006, 01:37 AMCaptainBlackQuote:

Originally Posted by**kwtolley**

to $\displaystyle -\infty$ as $\displaystyle x \to -\infty$, so the set of values for which $\displaystyle f(x)>0$ is:

$\displaystyle

(-3,0) \cup (1,\infty)

$

RonL - Jun 25th 2006, 01:42 AMkwtolleyanswer
thanks for looking at this problem, I see now where I messed this question.