# Math Help - graph

1. ## graph

on the coordinate system below carefully skecth the graph the soultion set of

y<1/3x^2+2x-5
3y-4x<=-2
y<0

in graphing the first inequality carfully plot and label the vertex of the parabola

2. Originally Posted by gumi
on the coordinate system below carefully skecth the graph the soultion set of

y<1/3x^2+2x-5
3y-4x<=-2
y<0

in graphing the first inequality carfully plot and label the vertex of the parabola
What problem are you having ? I assume that you have no problem with y<0 that is just the region below the x axis.

for y<1/3x^2+2x-5 first draw the curve y=1/3x^2+2x-5 and the region below the curve represents y<1/3x^2+2x-5 Do you understand why ?

for 3y-4x<=-2 rewrite this as this as y<=4/3x-2/3 now this a just a region below a line

Use this visual aid, your solution is the darkest blue area.

Bobak