on the coordinate system below carefully skecth the graph the soultion set of

y<1/3x^2+2x-5

3y-4x<=-2

y<0

in graphing the first inequality carfully plot and label the vertex of the parabola

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- Apr 20th 2008, 09:06 AMgumigraph
on the coordinate system below carefully skecth the graph the soultion set of

y<1/3x^2+2x-5

3y-4x<=-2

y<0

in graphing the first inequality carfully plot and label the vertex of the parabola - Apr 20th 2008, 09:25 AMbobak
What problem are you having ? I assume that you have no problem with y<0 that is just the region below the x axis.

for y<1/3x^2+2x-5 first draw the curve y=1/3x^2+2x-5 and the region below the curve represents y<1/3x^2+2x-5 Do you understand why ?

for 3y-4x<=-2 rewrite this as this as y<=4/3x-2/3 now this a just a region below a line

Use this visual aid, your solution is the darkest blue area.

Bobak