on the coordinate system below carefully skecth the graph the soultion set of
y<1/3x^2+2x-5
3y-4x<=-2
y<0
in graphing the first inequality carfully plot and label the vertex of the parabola
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on the coordinate system below carefully skecth the graph the soultion set of
y<1/3x^2+2x-5
3y-4x<=-2
y<0
in graphing the first inequality carfully plot and label the vertex of the parabola
What problem are you having ? I assume that you have no problem with y<0 that is just the region below the x axis.Quote:
Originally Posted by gumi
for y<1/3x^2+2x-5 first draw the curve y=1/3x^2+2x-5 and the region below the curve represents y<1/3x^2+2x-5 Do you understand why ?
for 3y-4x<=-2 rewrite this as this as y<=4/3x-2/3 now this a just a region below a line
Use this visual aid, your solution is the darkest blue area.
Bobak