[SOLVED] Convert polar coordinates to rectangular

**bilbobaggins** · April 16th 2008, 03:28 PM

1. $r=-3*sintheta$
2. $r*sectheta=3$

How do you make these into rectangular equations?

**mr fantastic** · April 16th 2008, 03:40 PM

Originally Posted by bilbobaggins

1. $r=-3*sintheta$
2. $r*sectheta=3$

How do you make these into rectangular equations?

1. $r = - 3 \sin \theta \Rightarrow r^2 = -3 r \sin \theta$ ......

2. $r \sec \theta = 3 \Rightarrow \frac{r}{\cos \theta} = 3 \Rightarrow r = 3 \cos \theta$ . Now use what you've learned from how I did 1.

**bilbobaggins** · April 16th 2008, 03:45 PM

Originally Posted by mr fantastic

1. $r = - 3 \sin \theta \Rightarrow r^2 = -3 r \sin \theta$ ......

2. $r \sec \theta = 3 \Rightarrow \frac{r}{\cos \theta} = 3 \Rightarrow r = 3 \cos \theta$ . Now use what you've learned from how I did 1.

I had already gotten to where you did in 2. 1 is still troubling me though, so you just multiplied both sides by r?

**mr fantastic** · April 16th 2008, 03:54 PM

Originally Posted by bilbobaggins

I had already gotten to where you did in 2. 1 is still troubling me though, so you just multiplied both sides by r?

That's what I did in 1, right? And after doing this, is it obvious what comes next?

**bilbobaggins** · April 16th 2008, 04:00 PM

Originally Posted by mr fantastic

That's what I did in 1, right? And after doing this, is it obvious what comes next?

x^2+y^2=-3y?

**mr fantastic** · April 16th 2008, 04:26 PM

Originally Posted by bilbobaggins

x^2+y^2=-3y?

(number 1, I assume)

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