No, it's symmetric about x=0.Originally Posted by daniel4616
For x>=0 it is the same as the line y=x
For x<0 it is the same as y=-x.
RonL
Hey, I have some question on college algebra
1. Is the line y=|x| symetric about the line y=x
2. How do you prove points A(-1,2) B(3,-2) C(-6,-3) are vertices of a right triangle?
3. given f(x)= 2x if 0<x<1, 1-x if 1=<x<2 , 0 if 1=<x=<3: find the domain,f(1), f(2), f(3), and f(0.1).
4. object thrown moves at a height in meters per second is represented With h(t)=20t-4.9t^2: find the height in x seconds, if time increases by 2 how migher is the object, how high does it move per second, if time increased by h how much higher is it?
A. You appear to have an error in the function definition, the way you haveOriginally Posted by daniel4616
defined it f(x) has two values for 1=<x<2. I will assume that the last
part of the definition should be: f(x)=0 2=<x=<3.
B. The domain is the set on which the function is defined. So in this case
f(x) is defined for all x such that 0<x=<3.
C. 1 lies in the second specified range so f(1)=1-1=0.
2 lies in the third specified range so f(2)=0, same for 3.
0.1 lies in the first specified range so f(0.1)=2x0.1=0.2.
RonL
I know how to do it, the problem is that when I find the lengths, I dont get an euqation equal to a2+b2=c2Originally Posted by CaptainBlack
I get AB= sqrt32
BC= sqrt 82
AC=sqrt 50
The height of an object thrown in the air depends on the time it has been thrown. One situation the hieght in meters of an object after t seconds can be represented by h(t)=20t-4.09t^2. Whats the hieghts after x seconds, if time nicreases by 2 how much higher is the object, how much higher is the object per second nicrease? how much higher is the object per unit increase?
Hello, daniel4616!
1. Is the line symetric about the line ?
Did you make a sketch?
Code:| * | * * | * * | * * | * - - - - * - - - - |
2. How do you prove points A(-1,2) B(3,-2) C(-6,-3) are vertices of a right triangle?
An alternate method . . .
Find the slopes of AB, BC, and AC.
Since and are negative reciprocals:
Therefore: and is a right triangle.
#4 is very badly worded . . .
4. An object thrown is a height represented by:
(a) Find the height in seconds
(b) If time increases by 2 seconds, how much higher is the object? . . . should be asked last
(c) How high does it move per second? . . . How high? or "how far"?
(d) If time increased by , how much higher is it? . . . but h represents height
In seconds, the height is:
Suppose time is increased from to .
Its height at time is: meters.
Its height at time is:
. . .
The difference is:
Therefore, it is: meters higher.
If , we have: meters higher.