# Thread: Problems that I SERIOUSLY need help with

1. ## Problems that I SERIOUSLY need help with

Ok I'm in 9th grade, and I really have trouble with Algebra. There's only 6 weeks of school left and I have like a 65 in math right now. I'd give anything to get at least a C.

Some of the problems we've been practicing in class are very difficult and I really hate my teacher because he won't help you unless you know what's going on, and how are you supposed to figure it out when you have no idea? He makes me feel like an idiot. I'm completely lost and if I pass the EOCT and I'm still just a few points from passing, he'll help me out. I'm going to be posting problems on here a few days a week so I can pass. If somebody could show me how to do these problems, It would be greatly appreciated.

Ok,
Some are
1. What values of X satisfy x + 2 = 24?

2.What is a factor of 6x - 13x + 5

3.What is the equation of the following line passing through points (5,5) and (5,10)?

4. What is the slope of the line with equation 3y + 5x = 4

I'd seriously appreciate anyone that can help me out on these,

Thank you very much,

2. Originally Posted by iownyou1230
Ok I'm in 9th grade, and I really have trouble with Algebra. There's only 6 weeks of school left and I have like a 65 in math right now. I'd give anything to get at least a C.

Some of the problems we've been practicing in class are very difficult and I really hate my teacher because he won't help you unless you know what's going on, and how are you supposed to figure it out when you have no idea? He makes me feel like an idiot. I'm completely lost and if I pass the EOCT and I'm still just a few points from passing, he'll help me out. I'm going to be posting problems on here a few days a week so I can pass. If somebody could show me how to do these problems, It would be greatly appreciated.

Ok,
Some are
1. What values of X satisfy x + 2 = 24?

2.What is a factor of 6x - 13x + 5

3.What is the equation of the following line passing through points (5,5) and (5,10)?

4. What is the slope of the line with equation 3y + 5x = 4

I'd seriously appreciate anyone that can help me out on these,

Thank you very much,
1) For this problem, go here and enter your left and right hand side of the equations. It will show you how to solve for x.

1 unknown variable equations

2) Is number 2 a typo? I'm assuming you mean y = 6x - 13x + 5. This simplifies to y = -7x + 5. This cannot be factored anymore. If you want a solution, set y to 0, we get x = 5/7.

3) Slope, Line Equation, Distance, and Midpoint Slope is not defined, because this is a vertical line. The math will show you how to calculate slope

4) 3y + 5x = 4 Rearrange your equation in y = mx + b form where slope is m.

3y = -5x + 4
y = -5/3 + 4/3

slope (m) = -5/3

3. ## ?

Originally Posted by mathceleb
1) For this problem, go here and enter your left and right hand side of the equations. It will show you how to solve for x.

1 unknown variable equations

2) Is number 2 a typo? I'm assuming you mean y = 6x - 13x + 5. This simplifies to y = -7x + 5. This cannot be factored anymore. If you want a solution, set y to 0, we get x = 5/7.

3) Slope, Line Equation, Distance, and Midpoint Slope is not defined, because this is a vertical line. The math will show you how to calculate slope

4) 3y + 5x = 4 Rearrange your equation in y = mx + b form where slope is m.

3y = -5x + 4
y = -5/3 + 4/3

slope (m) = -5/3
For number 4 I don't understand how you would get that. What do you do in order to get that?

4. Originally Posted by iownyou1230
For number 4 I don't understand how you would get that. What do you do in order to get that?
The standard form for a line equation is y = mx + b where y is your m is your slope.

So we rearrange our equation just like we did in Question 1, but this time, we want to isolate y on one side, and everything else on the other. Once you have y isolated, slope is just your m coefficient in front of x.

5. Looks like there's a typo, it should read y = -5/3x + 4/3, ie. there should be an x in there.

The slope is then easy to find, it's simply the number (here the fraction -5/3) in front of the x term.