Hi guys I have a few questions that I am totally lost on.

1) Write as a single loagrithm: 4lnx - 2(lnx^3 + 4lnx)

2) Solve: 2^x = 3^(x+3)

3) Solve: log(x^2 -1) = 2 + log (x+1)

Thanks in advance!!

Results 1 to 7 of 7

- Apr 15th 2008, 10:29 AM #1

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- Apr 15th 2008, 10:36 AM #2
Hello,

Remember that $\displaystyle \ln(a^b)=b \ln(a)$

So how would you transform $\displaystyle \ln(x^3)$ in the first one ?

For the second one, this is the same : compose each side with logarithm.

For the third one, note that x²-1=(x-1)(x+1)

Then remember that $\displaystyle \ln(ab)=\ln(a)+\ln(b)$

- Apr 15th 2008, 10:55 AM #3

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- Apr 15th 2008, 10:56 AM #4

- Apr 15th 2008, 10:57 AM #5

- Apr 15th 2008, 10:57 AM #6

- Apr 15th 2008, 11:05 AM #7

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