Exponential and Logarithmic Equations

**kbryant05** · June 15th 2006, 05:55 AM

Good Morning,

My problem is: Use a calculator with a y^x key or ^ key to solve the following.

The 1986 explosion at Chernobyl nuclear power plant in the former Soviet Union sent about 1000 kilograms of radioactive cesium-137 into the atmosphere. The functon f(x)=1000(0.5)^ x over 30 describes the amount, f(x), in kilograms of cesium-137 remaining in Chernobyl x years after 1986. If even 100 kilograms of cesium-137 remain in Chernobyls atmosphere, the area is considered unsafe for human habitation. Find f(80) and determine if Chernobyl will be safe for human habitation by 2066.

**earboth** · June 15th 2006, 06:28 AM

Originally Posted by kbryant05

Good Morning,

My problem is: Use a calculator with a y^x key or ^ key to solve the following.

The 1986 explosion at Chernobyl nuclear power plant in the former Soviet Union sent about 1000 kilograms of radioactive cesium-137 into the atmosphere. The functon f(x)=1000(0.5)^ x over 30 describes the amount, f(x), in kilograms of cesium-137 remaining in Chernobyl x years after 1986. If even 100 kilograms of cesium-137 remain in Chernobyls atmosphere, the area is considered unsafe for human habitation. Find f(80) and determine if Chernobyl will be safe for human habitation by 2066.

Hello,

I hope that you are allowed to use the ln-button too.

Plug in the value(s) you know into the equation:

$f(x)=1000 \cdot \left( \frac{1}{2} \right)^{\frac{x}{30}$

That means you have to solve the equation for x:

$80=1000 \cdot \left( \frac{1}{2} \right)^{\frac{x}{30}$

The next steps should be:

$0.08=\left( \frac{1}{2} \right)^{\frac{x}{30}$

The exponent x/30 is a logarithm to the base 0.5. Use the base-change-formula (I am not sure, if this is the right expression. But maybe you recognize the name when you have a look at the solution)

$\frac{\ln(0.08)}{\ln(0.5)}=\frac{x}{30}$

So:

$30\cdot\frac{\ln(0.08)}{\ln(0.5)}=x$ . That means x is round about 110 years. In 2066 Chernobyl will be one of the most dangerous places on earth.

Greetings

EB

**kbryant05** · June 15th 2006, 06:42 AM

Thanks Earboth. I don't think that answer is very comforting for anyone living in that area. It's actually really frightening.
Yes we are allowed to use the in button too!!

Have a great day!

**Quick** · June 15th 2006, 12:08 PM

Originally Posted by earboth

That means x is round about 110 years. In 2066 Chernobyl will be one of the most dangerous places on earth.

Greetings

EB

I don't agree. You said that $f(x)=f(80)=80$ , which would solve the equation for "how many years does it take to reach 80kg" but the question says it is $f(x)=f(80)$ so $x=80$

So you would substitute 80 for x instead of the function of x.

$f(x)=1000(0.5)^{\frac{x}{30}}$

$f(80)=1000(0.5)^{\frac{80}{30}}$

$f(80)=1000(0.5)^{\frac{8}{3}}$

$f(80)=1000(0.157490131236859)$

$f(80)=157.490131236859$

So, yes it is still lethal.

Thread: Exponential and Logarithmic Equations

LinkBack

Thread Tools

Display