1. ## solve quadratics by factoring

solve the following quadratics by factoring

x^2=6x

x^2=6x-8

6x^2-13x+6=0

5x^2-17x+14=0

12x^2+x=1

2. ## Ok

Originally Posted by gumi
solve the following quadratics by factoring

x^2=6x

x^2=6x-8

6x^2-13x+6=0

5x^2-17x+14=0

12x^2+x=1
Why dont you show us some work and we will critique you...for the first one I will give you that $(x-3)^2=9$

3. for the 2nd one i got
(x-3)^2=1

is that right?

4. ## Haha

Originally Posted by gumi
for the 2nd one i got
(x-3)^2=1

is that right?
Yes that is correct...very good...but it can be simpler factor it into $(x-4)(x-2)$

5. Hello,

For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^

x²=6x
x²-6x=0
x(x-6)=0

So...

6. ## yeah I know

Originally Posted by Moo
Hello,

For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^

x²=6x
x²-6x=0
x(x-6)=0

So...
But on another post of theirs it asked for completing the square so I just took the liberty of assuming that is what she meant

7. the 3rd one i got
(2 + -3x)(3 + -2x) = 0

is that right?