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Math Help - solve quadratics by factoring

  1. #1
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    solve quadratics by factoring

    solve the following quadratics by factoring

    x^2=6x



    x^2=6x-8



    6x^2-13x+6=0



    5x^2-17x+14=0


    12x^2+x=1
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Ok

    Quote Originally Posted by gumi View Post
    solve the following quadratics by factoring

    x^2=6x



    x^2=6x-8



    6x^2-13x+6=0



    5x^2-17x+14=0


    12x^2+x=1
    Why dont you show us some work and we will critique you...for the first one I will give you that (x-3)^2=9
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  3. #3
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    for the 2nd one i got
    (x-3)^2=1

    is that right?
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  4. #4
    MHF Contributor Mathstud28's Avatar
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    Haha

    Quote Originally Posted by gumi View Post
    for the 2nd one i got
    (x-3)^2=1

    is that right?
    Yes that is correct...very good...but it can be simpler factor it into (x-4)(x-2)
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  5. #5
    Moo
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    Hello,

    For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^

    x=6x
    x-6x=0
    x(x-6)=0

    So...
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  6. #6
    MHF Contributor Mathstud28's Avatar
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    yeah I know

    Quote Originally Posted by Moo View Post
    Hello,

    For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^

    x=6x
    x-6x=0
    x(x-6)=0

    So...
    But on another post of theirs it asked for completing the square so I just took the liberty of assuming that is what she meant
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  7. #7
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    the 3rd one i got
    (2 + -3x)(3 + -2x) = 0

    is that right?
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